大体思路

如果发总金额为 m mm 的 n nn 个红包,先用一个长度为 n nn 的临时数组 a aa 存放 n nn 个随机双精度小数 ,然后用 s u m sumsum 表示数组 a aa 的和,每个红包的金额

代码

import java.util.arrays;
import java.util.random;
import java.math.*;
import java.util.scanner;

public class main {
  public static long now_time;
  public static long seed;
  public static int[] get_red_packets(int money, int num) {
    random random = new random(seed);
    seed = random.nextlong();
    int[] res = new int[num];
    double[] temp=new double[num];
    double sum = 0;
    int sum2 = 0;
    for (int i = 0; i < num; i++) {
      temp[i] = random.nextdouble();
      sum += temp[i];
    }
    for (int i = 0; i < num; i++) {
      res[i] = 1+ (int)(temp[i] / sum * (money-num));
      sum2 += res[i]-1;
    }
    res[random.nextint(num)]+=money-sum2-num;
    return res;
  }

  public static void show(int[] red_packet){
    system.out.println("红包 : " + arrays.tostring(red_packet));
  }

  public static void main(string[] args) {
    int num, money;
    scanner scanner = new scanner(system.in);
    now_time = system.currenttimemillis();
    random init_random = new random(now_time);
    seed = init_random.nextlong();
    system.out.println("请输入要分发的红包数量:");
    num = scanner.nextint();
    system.out.println("请输入要分发的红包总金额(分):");
    money = scanner.nextint();
    int a[] = get_red_packets(money,num);
    show(a);
  }
}

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