Python OpenCV寻找两条曲线直接的最短距离

本文实例为大家分享了python opencv两条曲线直接最短距离的寻找方法，供大家参考，具体内容如下

import numpy as np
import math
import cv2

def cal_pt_distance(pt1, pt2):
  dist = math.sqrt(pow(pt1[0]-pt2[0],2) + pow(pt1[1]-pt2[1],2))
  return dist

font = cv2.font_hershey_simplex
img = cv2.imread('01.png')
#cv2.imshow('src',img)
gray = cv2.cvtcolor(img,cv2.color_bgr2gray)
gray = cv2.gaussianblur(gray, (3,3), 0)

ret,thresh = cv2.threshold(gray, 150, 255, cv2.thresh_binary)
image,contours,hierarchy = cv2.findcontours(thresh, cv2.retr_external, cv2.chain_approx_none)
#thresh,contours,hierarchy = cv2.findcontours(thresh, cv2.retr_list, cv2.chain_approx_none)

flag = false
mindist = 10000
minpt0 = (0,0)
minpt1 = (0,0)
for i in range(0,len(contours[1])):#遍历所有轮廓
  pt = tuple(contours[1][i][0])
  #print(pt)
  min_dis = 10000
  min_pt = (0,0)
  #distance = cv2.pointpolygontest(contours[1], pt, false)
  for j in range(0,len(contours[0])):
    pt2 = tuple(contours[0][j][0])
    distance = cal_pt_distance(pt, pt2)
    #print(distance)
    if distance < min_dis:
      min_dis = distance
      min_pt = pt2
      min_point = pt
  if min_dis < mindist:
    mindist = min_dis
    minpt0 = min_point
    minpt1 = min_pt
  temp = img.copy()
  cv2.drawcontours(img,contours,1,(255,255,0),1)
  cv2.line(temp,pt,min_pt,(0,255,0),2,cv2.line_aa)
  cv2.circle(temp, pt,5,(255,0,255),-1, cv2.line_aa)
  cv2.circle(temp, min_pt,5,(0,255,255),-1, cv2.line_aa)
  cv2.imshow("img",temp)
  if cv2.waitkey(1)&0xff ==27: #按下esc键退出
    flag = true
    break
  if flag:
    break

cv2.line(img,minpt0,minpt1,(0,255,0),2,cv2.line_aa)
cv2.circle(img, minpt0,3,(255,0,255),-1, cv2.line_aa)
cv2.circle(img, minpt1,3,(0,255,255),-1, cv2.line_aa)
cv2.puttext(img,("min_dist=%0.2f"%mindist), (minpt1[0],minpt1[1]+15), font, 0.7, (0,255,0), 2)

cv2.imshow('result', img)
cv2.imwrite('result.png',img)
cv2.waitkey(0)
cv2.destroyallwindows()

原图：

结果图：

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