Python统计节假日剩余天数的脚本

目录

• 1、前言
• 2、倒计时脚本

1、前言

如何快速的想了解距离节假日还有多少天？

接下来使用python脚本来解决这个问题。

2、倒计时脚本

脚本代码：

#!/usr/bin/env python
# -*- coding: utf-8 -*-
 
from colorama import init, fore
from zhdate import zhdate
import datetime
def get_week_day(date):
    week_day_dict = {
        0: '星期一',
        1: '星期二',
        2: '星期三',
        3: '星期四',
        4: '星期五',
        5: '星期六',
        6: '星期天',
    }
    day = date.weekday()
    return week_day_dict[day]
def time_parse(today):
    distance_year = (datetime.datetime.strptime(f"{today.year}-01-01", "%y-%m-%d").date() - today).days
    distance_year = distance_year if distance_year > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-01-01", "%y-%m-%d").date() - today).days
    distance_big_year = (zhdate(today.year, 1, 1).to_datetime().date() - today).days
    distance_big_year = distance_big_year if distance_big_year > 0 else (
            zhdate(today.year + 1, 1, 1).to_datetime().date() - today).days
    distance_4_5 = (datetime.datetime.strptime(f"{today.year}-04-05", "%y-%m-%d").date() - today).days
    distance_4_5 = distance_4_5 if distance_4_5 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-04-05", "%y-%m-%d").date() - today).days
    distance_5_1 = (datetime.datetime.strptime(f"{today.year}-05-01", "%y-%m-%d").date() - today).days
    distance_5_1 = distance_5_1 if distance_5_1 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-05-01", "%y-%m-%d").date() - today).days
    distance_5_5 = (zhdate(today.year, 5, 5).to_datetime().date() - today).days
    distance_5_5 = distance_5_5 if distance_5_5 > 0 else (
            zhdate(today.year + 1, 5, 5).to_datetime().date() - today).days
    distance_8_15 = (zhdate(today.year, 8, 15).to_datetime().date() - today).days
    distance_8_15 = distance_8_15 if distance_8_15 > 0 else (
            zhdate(today.year + 1, 8, 15).to_datetime().date() - today).days
    distance_10_1 = (datetime.datetime.strptime(f"{today.year}-10-01", "%y-%m-%d").date() - today).days
    distance_10_1 = distance_10_1 if distance_10_1 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-10-01", "%y-%m-%d").date() - today).days
    # print("距离周末: ", 5 - today.weekday())
    # print("距离元旦: ", distance_year)
    # print("距离大年: ", distance_big_year)
    # print("距离清明: ", distance_4_5)
    # print("距离劳动: ", distance_5_1)
    # print("距离端午: ", distance_5_5)
    # print("距离中秋: ", distance_8_15)
    # print("距离国庆: ", distance_10_1)
    time_ = [
        {"v_": 5 - 1 - today.weekday(), "title": "周末"}, # 距离周末
        {"v_": distance_year, "title": "元旦"}, # 距离元旦
        {"v_": distance_big_year, "title": "过年"}, # 距离过年
        {"v_": distance_4_5, "title": "清明节"}, # 距离清明
        {"v_": distance_5_1, "title": "劳动节"}, # 距离劳动
        {"v_": distance_5_5, "title": "端午节"}, # 距离端午
        {"v_": distance_8_15, "title": "中秋节"}, # 距离中秋
        {"v_": distance_10_1, "title": "国庆节"}, # 距离国庆
    ]
    time_ = sorted(time_, key=lambda x: x['v_'], reverse=false)
    return time_
def countdown():
    init(autoreset=true)
    today = datetime.date.today()
    now_ = f"{today.year}年{today.month}月{today.day}日"
    week_day_ = get_week_day(today)
    print(f'\n\t\t {fore.green}{now_} {week_day_}')
    str_ = '''
         开始!
    '''
    print(f'{fore.red}{str_}')
    time_ = time_parse(today)
    for t_ in time_:
        print(f'\t\t {fore.red}距离{t_.get("title")}还有: {t_.get("v_")}天')
    tips_ = '''
         结束!
    print(f'{fore.red}{tips_}')
    print(f'\t\t{fore.cyan} 公众号：alltests软件测试\n')
if __name__ == '__main__':
    countdown()

在pycharm上执行结果：

在终端上执行结果：

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